an object is thrown vertically upwards and rises to a height of 20 m. calculate (i) the velocity with which the object was thrown upwards, (ii) the time taken by the object to reach the highest point. [g= 10m/s^2
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Given
S=20m
g=10m/s² = > a=-10m/s²
Using
v²-u²=2as
2x(-10)x20 =0²-u² (at miximum height v=0)
-400=-u²
U²=400
U=20m/s
Time.
a=(v-u) /t
T=0-20/-10
T=-20/-10=2
T=2 second
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S=20m
g=10m/s² = > a=-10m/s²
Using
v²-u²=2as
2x(-10)x20 =0²-u² (at miximum height v=0)
-400=-u²
U²=400
U=20m/s
Time.
a=(v-u) /t
T=0-20/-10
T=-20/-10=2
T=2 second
This is ur ans hope it will help you in case of any doubt comment below
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