Question

An object is thrown vertically upwards and rises to a height of 20 cm. Calculate: a) The velocity with which the object was thrown upwards. b) The time taken by the object to reach the highest point. ( g= 10m/s²)

Answer 1

Answer:

v=20m/s

T=2sec

Explanation:

$h = u {}^{2} \div 2g \\ \\ t = \sqrt{2h \div g}$

hope these help u

if help then mark as Brainliest

Answer 2

Explanation:

a)

We know that

v2 - u2 = 2as

0 - u2 = 2 *-10 *0.2

Therefore

u = 2m/s

b)

v = u + at

0 = 2 - 10t

Therefore

t = 0.2 sec