An object is thrown vertically upwards and rises to a height of 10 m. Calculate
(i) the velocity with which the object was thrown upwards and
(ii) the time taken by the object to reach the highest point.
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distance =10m
V=0m/s
g = -9.8m/s^2 ( we take value negative because it is against gravity)
1) v^2 - u^2 = 2gs
0^2 - u^2 = 2×-9.8×10
0 - u^2 = -196
-u^2 = -196
u =. 14m/s
2) v=u+gt
0=14+-9.8 ×t
-14= -9.8t
-14/-9.8 = t
1.42 =t
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