Question

an object is thrown vertically upwards and rises to a height of 1 m .calculate (i) velocity with which the object was thrown upwards and (ii) the time taken by the objects to reach the highest point
please ans this question , pls dont give unwanted answers if so, the ans will be reported​

Answer 1

Answer:

If the final velocity is v, initial velocity is u and distance traveled or height is S, then

             $v^{2} = u^{2} + 2aS$

At the highest point final velocity is zero.

            $0= u^{2} + 2gS$

Acceleration due to gravity g = 10m/$s^{2}$ is negative as the object is thrown vertically upwards.

•              $-u^{2}= -2gS$

                       $u^{2}= 2gS$   ⇒   $u^{2}= 2*10*1$

                      Initial velocity, $u = \sqrt{20} m/s$

• v = u + gt

       t = [v-u]/g

         = 0.45s