Question

An object is thrown vertically upwards and rises to a height of 10 m. Calculate the velocity with which the object was thrown upwards? Take g=9.8 m/s2​

Answer 1

h=10 m
v= 0 m/s
u=?
g=9.8m/s^2

according to third equation of motion
v2-u2= 2gh
0-u2= 2*9.8*10
u2= 2*98
u=√2*98
u=14m/s

Answer 2

Explanation:

Answer:

$\setlength{\unitlength}{1mm}\begin{picture}(8,2)\thicklines\multiput(9,1.5)(1,0){50}{\line(1,2){2}}\multiput(35,7)(0,4){13}{\line(0,1){2}}\put(10.5,6){\line(3,0){50}}\put(35,60){\circle*{10}}\put(37,7){\large\sf{u = ?}}\put(37,55){\large\sf{v = 0 m/s}}\put(18,61){\large\textsf{\textbf{Object}}}\put(30,40){\vector(0, - 4){32}}\put(30,35){\vector(0,4){22}}\put(12,35){\large\sf{h = 10 m}}\end{picture}$

• Height = 10 m

• Velocity = 0 m/s

• gravity = - 10 m/s²

• Initial Velocity ( u ) = ?

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$\underline{\bigstar\:\textsf{Using Third Equation of Gravity :}}$

$:\implies\sf (v)^2-(u)^2=2gh\\\\\\:\implies\sf (0)^2-(u)^2=2 \times (-10) \times 10\\\\\\:\implies\sf -(u)^2= - 200\\\\\\:\implies\sf (u)^2= 200\\\\\\:\implies\sf u = \sqrt{200}\\\\\\:\implies\underline{\boxed{\sf u = 14.1\:m/s}}$

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