An object is thrown vertically upwards with a velocity 20 m per second.Calculate the maximum height it could acquire.(g=10m/s^2).
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Answered by
2
u =20 m/s
v = 0 m/s {at upward case v=o and' g 'become negative}
g = 10 m/s²
using, v²=u² +2gh
0²=20²+2*-10*h
0 =400-20h
-400 =-20h
-400/-20=h
∴ h=20 m
v = 0 m/s {at upward case v=o and' g 'become negative}
g = 10 m/s²
using, v²=u² +2gh
0²=20²+2*-10*h
0 =400-20h
-400 =-20h
-400/-20=h
∴ h=20 m
Answered by
2
We know that initial velocity is 20m/s.
Final velocity is 0m/s.
Gravity is 10m/s^2
Using v^2 = u^2+ 2gS
We get,
Height as 20m
Final velocity is 0m/s.
Gravity is 10m/s^2
Using v^2 = u^2+ 2gS
We get,
Height as 20m
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