Question

An object is thrown vertically upwards with a velocity n times its escape velocity.What will be its velocity once it exits Earths Gravitational well?​

Answer 1

Answer:

Kinetic energy at a larger distance = PE + KE at the surface of the earth

2

1

mv

2

=−

R

GMm

+

2

1

m(nv

e

)

2

But, the escape velocity,

v

e

2

=

R

2GM

So,

R

2

GMm

=

2

1

mv

e

2

Hence,

2

1

mv

2

=−

2

1

mv

e

2

+

2

1

mn

2

v

e

2

v

2

=−v

e

2

+n

2

v

e

2

v=

(n

2

−1)

v

e

hope this helps you mate

Answer 2

Answer:

Escape Velocity is referred to as the minimum velocity needed by anybody or object to be projected to overcome the gravitational pull of the planet earth. In other words, the minimum velocity that one requires to escape the gravitational field is escape velocity.

I hope this is correct answer

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