Physics, asked by PanduDeepak663, 1 year ago

An object is thrown vertically upwards with a velocity of 19.6 meter second calculate the distance and displacement of the object after 3 seconds

Answers

Answered by tanya177

2

Answer:

58.8 metres

Explanation:

Distance = Speed × Time

Therefore ,distance =3×19.6=58.8 metres

Similarly, Displacement = velocity × time

Therefore,Velocity= 3×19.6=58.8 metres

Hope it will help you

please let me know of answer is correct ..

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