Question

An object is thrown vertically upwards with a velocity of 60 m/s.After what time will it strike the ground? use g= 10m/s^2.​

Answer 1

Here is ur answer:

Let the time of the particle be t

using

v = u- gt

$t = \frac{ - u}{ - g} = \frac{60}{10} = 6s$

As the time of ascent is equal to the time of descent,

therefore

t= 6+6 =12s

Answer 2

12 s

Let 't' be the time of ascent of object

v = u- gt

v - velocity

u - initial velocity

g - gravitational force

t = $\frac{-u}{-g}$ = $\frac{60}{10}$ = 6s

As the time of ascent is equal to the time of descent, therefore

t = 6+6 = 12s

After 12s the object will it strike the ground

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