Question

An object is thrown vertically upwards with a velocity of 60 m/s.After what time will it strike the ground? use g= 10m/s^2​

Answer 1

Answer:

Explanation:

Height stone will rise to above the building.  

u^2 = 2as  

42^2 = 2 x 9.8 x s  

s = 90m  

Height of stone above the ground:  

s = 90 + 18  

s= 108 m  

Velocity just before it hits the ground:  

v^2 = 2as  

v^2 = 2 x 9.8 x 108  

v = 46 m/s.  

After the stone reaches its maximum height, the velocity is ZERO. Gravity slowed it down to a point where it stopped rising and immediately started falling.