Question

An object is thrown vertically upwards with an initial velocity of 100m/s. Find the time taken to reach maximum height. Also find the maximum height reached. (Take g= 10m/s2)

Answer 1

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Given, u = 100 m/s; v = 0 m/s; a = g = -10m/s2

➡Time taken to reach maximum height

t = (v - u)/a = (0 - 100) / (-10) = 10s

➡Maximum height reached is

$s = h = \frac{u}{t {}^{2} } {at }^{2} \\ (100 \times 10) + \frac{1}{2} \times ( - 10) \times {10 }^{2} \\ =1 000 - 500 \\ = 500m$

➡Velocity after 5 second

v = u + at = 100 + (-10 x 5)

= 50 m/s