an object is thrown with a velocity it travels 40m in 3rd second and reaches the ground in 10 sec calculate the distance travelled in 10 sec and 10th second
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Answer:
"Equation of motion.
v = u + at
v is the final velocity. u is the initial velocity (40 m/s) & t is 2 s. a is the acceleration.
v = 40 + (-10 x 2)
v = 20 m/s
The velocity is 20 m/s upwards.
The value of -g is substituted for a as the object is moving against gravity."
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Answer:
D= S/T
D= 10/40
0 to 0 Cancel
D= 1/4
Explanation:
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