Question

An object is thrown with a velocity of 60 m/s making an angle of 30 degrees with horizontal then the range of object is ....​

Answer 1

Answer:

Hello ✌✌

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$range = \frac{ {u}^{2} sin2θ}{g}$

$= \frac{60 \times 60}{10} \times \frac{ \sqrt{3} }{2}$

$= 180 \sqrt{3}$

$\:$

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