Question

An object is thrown with a velocity of 8m/s. It reaches at certain height in 2 seconds.What will be its velocity when it reaches the highest point?​

Answer 1

Step-by-step explanation:

ANSWER

The ball is thrown upwards.

∴ Acceleration due to gravity =−9.8m/s

2

Final velocity = 0m/s

Initial velocity =25 m/s

Distance =35 m

Time =1.5 sec

To find total distance traveled: the distance traveled by the ball in upward and downward motion will be the same.

Hence, the total distance will be 35 m+35 m=70 m

To find position after 2 sec

Using the formula:

s=ut+

2

1

at

2

s=25×2+

2

1

×−9.8×(2)

2

s=50+(−19.6)

s=30.4 m