an object is thrown with initial velocity of hundred metres per second then find the maximum height of the object
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Answer:
Let the initial velocity = u
final velocity = v
v= 0 m/s
s = 500 m
2gs = v
2
−u
2
2 (-10) 500 = u
2
u = 100 m/s
v = u + at
0 = 100 - 10 t
t = 10 s
total time taken = 20 sec.
Explanation:
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