Question

An object is trown up from ground with speed of 50m/s it's distance above ground level 1sec later is

Answer 1

Hey ▪

We will use second equation of uniformly accelerated motion 《 s= ut + 1/2 at^2》

Given:

• U = 50m/s

• T = 1 sec

• A = 10 N ( Gravitational Acceleration)

So, Put the values in the equation: 《 s= ut + 1/2 at^2》

$s = (50 \times 1) + ( \frac{1}{2} \times 10 \times 1^{2} )$

S = 50 + 5

S = 55m