an object length 3cm placed at distance of 20cm from a converging lens of 15 cm focal length. Find the position and nature of the image.
please answer very urgent
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Answer:
object distance u = -20 cm
focal length f = 15 cm
after applying the lens formula
1/f = 1/v - 1/u
1/15 = 1/v + 1/ 20
1/15 - 1/20 = 1/v
1/60 = 1/v
hence the image distance will be 60 cm on the right hand side of the lens
m = - v/u
= -60/-20
= +3
therefore the image will be enlarged
hope this helps love
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