An object located 32 cm in
front of lens froms And Image
on a screen 8 cm behind The
lens Find The focal length
Magnification is the lens Conserving
on Diveazing
Answers
Answered by
25
Answer:
1/u + 1/v = 1/f
1/f = (v + u)/u*v
f = u*v/(v + u)
f = 8.03cm*32.5cm/(32.5cm + 8.03cm)
f = 6.439057488cm
f = 6.44cm
m = v/u
m = 8.03cm/32.5cm
m = x0.247076923
m = x0.247
u = object distance
v = image distance
f = focal length
m = magnification
Explanation:
hope it helps you
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Answered by
1
Answer:
Explanation:1/u + 1/v = 1/f
1/f = (v + u)/u*v
f = u*v/(v + u)
f = 8.03cm*32.5cm/(32.5cm + 8.03cm)
f = 6.439057488cm
f = 6.44cm
m = v/u
m = 8.03cm/32.5cm
m = x0.247076923
m = x0.247
u = object distance
v = image distance
f = focal length
m = magnification
Explanation:
hope it helps you
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