an object measures 5N in air and 2N when put in water . find out buoyant force which acts on it
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Answered by
19
bouyant force =weight lost by the body
=weight in air - weight in water
=5N-2N=3N
=weight in air - weight in water
=5N-2N=3N
Answered by
17
Weight in air = 5N
Weight in water = 2N
Loss in weight = 5N-2N
= 3N
Buoyant force = 3N
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Weight in water = 2N
Loss in weight = 5N-2N
= 3N
Buoyant force = 3N
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