Question

An object moved in a circular path of radius 21m such that it made an angle of 30o . What is the distance (in meter) covered by the object?

Answer 1

Step-by-step explanation:

use formula

s=r×theta

where r=radius

S=21×π/6

s=11m

Answer 2

Answer:

The covered distance is 11 meters.

Given:  

An object moved in a circular path of radius 21m such that it made an angle of $30^{\circ}$.  

To find:

The distance (in meter) covered by the object.

Solution:

Radius = r = 21 m

Angle = $\theta$ = 30 degrees $= \frac{\pi}{6}$

By formula, s = r \times$\theta$

S = $21\times \frac{\pi}{6}=7 \times \frac{\pi}{3}$=11

Result:

The distance covered = 11 m.