An object moves 18 m in the first 3 so, 22 m in the next 3 s and 14 m in the last 3 s. What is its average speed?
Answers
Answer:
The average speed of the object will be 6 m/s.
Explanation:
By definition, Average speed is the ratio of the "total distance travelled by an object", to the "total time taken by the object" to cover the distance, or,
\text { Average Speed } = \frac { \text { the total distance travelled by an object } } { \text { the total time taken by the object to cover the distance } } Average Speed =
the total time taken by the object to cover the distance
the total distance travelled by an object
According to the question,
Total distance travelled by an object
= 18m + 22m + 14m = 54m
Total time taken by the object to cover 54m
= 3s + 3s + 3s = 9s
∴ Average Speed =\frac {(54 m)}{(9 s)} =6m/s=
(9s)
(54m)
=6m/s
= 6 m/s (Ans.)
Thus, the average speed of the object will be 6 m/s.
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Answer:
6m/s
Explanation:
first 3 sec it travels 18 m so speed becomes 6m/s
again in second 3 sec it travels 22m so speed becomes 22/3 m/s
again in last 3 sec it travels 14 m so speed becomes 14/3 m/s
hence
avg speed = [6m/s+22/3 m/s+14/3 m/s ] /3
avg speed comes out to be 6 m/s