Physics, asked by Tanvi7136, 9 months ago

An object moves 18 m in the first 3 so, 22 m in the next 3 s and 14 m in the last 3 s. What is its average speed?

Answers

Answered by rk0562527
0

Answer:

The average speed of the object will be 6 m/s.

Explanation:

By definition, Average speed is the ratio of the "total distance travelled by an object", to the "total time taken by the object" to cover the distance, or,

\text { Average Speed } = \frac { \text { the total distance travelled by an object } } { \text { the total time taken by the object to cover the distance } } Average Speed =

the total time taken by the object to cover the distance

the total distance travelled by an object

According to the question,

Total distance travelled by an object

= 18m + 22m + 14m = 54m

Total time taken by the object to cover 54m

= 3s + 3s + 3s = 9s

∴ Average Speed =\frac {(54 m)}{(9 s)} =6m/s=

(9s)

(54m)

=6m/s

= 6 m/s (Ans.)

Thus, the average speed of the object will be 6 m/s.

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Answered by rohitsharmayuvi2002
0

Answer:

6m/s

Explanation:

first 3 sec it travels 18 m so speed becomes 6m/s

again in second 3 sec it travels 22m so speed becomes 22/3 m/s

again in last 3 sec it travels 14 m so speed becomes 14/3 m/s

hence

avg speed = [6m/s+22/3 m/s+14/3 m/s ] /3

avg speed comes out to be 6 m/s

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