Question

An object moves 18m in the first 3s , 22m in the next 3s and 14 m in the last 3 s. what is the average speed ?

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Answer 1

Explanation:

Total distance =18+22=40

Total time=3+3=6 seconds

Average speed =total distance/total time

its means=40/6 m/s =6.6 metre/seconds

which is also =24 hours/kilometers

Answer 2

Answer:

$The \: average \: speed \: of \: the \\ object \: will \: be \: 6 m/s.$

Explaination:

$By \: definition,Average \: speed \: is \\ the \: ratio \: of \: the \: "total \: distance \: \\ travelled \: by \: an \: object",to \: the \\ "total \: time \: taken \: by \: the \\ object" \: to \: cover \: the \: distance, \: or, \\ Average \: Speed = \frac{the \: total \: distance \: travelled \: by \: an \: object}{the \: total \: time \: taken \: by \: the \: object \: to \: cover \: the \: distance} \\ \\ According \: to \: the \: question, \\ Total \: distance \: travelled \: by \: an \: object \\ = 18m + 22m + 14m = 54m \\ Total \: time \: taken \: by \: the \\ object \: to \: cover \: 54m \\ = 3s + 3s + 3s = 9s \\ ∴ Average \: Speed = \frac{(54m)}{(9s)} = 6m/s \\ = 6 m/s (Ans.) \\ Thus, \: the \: average \: speed \\ of \: the \: object \: will \: be \: 6 m/s.$

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