an object moves 20m in the first s 45, 24m in the next 4s and 16m in the last 4s then what is it's average speed
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Answer:
Explanation:
Distance1 = 20 m
Time1 = 4 s
Distance2 = 20 m
Time 2 = 10 s
Total Distance(D) = 20m + 20m = 40m
Total Time(T) = 4s + 10s = 14s
Average Speed = Total Distance(D) / Total Time(T) = D/T = 40/14
= 2.857 m/s
Answered by
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20+24+16
——————
45+4+4
=> 60
——-
53
=> 1.132075471698113
——————
45+4+4
=> 60
——-
53
=> 1.132075471698113
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