Question

An object moves 26m in the first 3s and 16m in the next 3s while it travels 18m in the last 3s calculate average speed

Answer 1

Explanation:

⛧Average speed of a moving body is defined as the ratio of the total distance covered by the body to the total time taken by it to complete the motion.⛧

➡Now in this case there is two motion .

In first case distance covered =18m.

In second case distance covered =22m.

So➡ total distance covered =40m.

In first case time taken =3secs.

In second case time taken =3secs.

So➡ total time taken =6secs.

So :- Averagespeed=totaldistancecovered/totaltimetaken.

Averagespeed=40m/6secs.

⛧ Averagespeed=6.667m/s. ⛧

Which is also equal to⛧ 24km/hr. ⛧

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Hope this may help you.

Answer 2

Given :-

• An object moves 26m in the first 3s and 16m in the next 3s while it travels 18m in the last 3s.

To find :-

• Average speed of an object

Solution :-

✶ In first case ✶

• Distance travelled (D1) = 26m
• Time taken (t1) = 3s

✶ In second case ✶

• Distance travelled (D2) = 16m
• Time taken (t2) = 3s

✶ In third case ✶

• Distance travelled (D3) = 18m
• Time taken (t3) = 3s

Now, as we know that

• Average speed is defined as total distance travelled by an object in total amount of time.

• Average speed measures the average rate of speed over a trip.

So,

→ Average speed = total distance travelled/total time taken

→ Average speed = D1 + D2 + D3/t1 + t2 + t3

→ Average speed = 26 + 16 + 18/ 3 + 3 + 3

→ Average speed = 60/9

→ Average speed = 6.66m/s

Hence,

• Average speed of an object i.e 6.66m/s