Question

An object moves 26m in the first 3s and 16m
in the next 3s while it travels 18m in the last
3s calculate average speed
​

Answer 1

Given :-

• An object moves 26m in the first 3s and 16m in the next 3s while it travels 18m in the last 3s.

To find :-

• Average speed of an object

Solution :-

✭ In first case ✭

• Distance travelled (D1) = 26m
• Time taken (t1) = 3s

✭ In second case ✭

• Distance travelled (D2) = 16m
• Time taken (t2) = 3s

✭ In third case ✭

• Distance travelled (D3) = 18m
• Time taken (t3) = 3s

Now, as we know that

• Average speed is defined as total distance travelled by an object in total amount of time.

• Average speed measures the average rate of speed over a trip.

So,

• → Average speed = total distance travelled/total time taken

• → Average speed = D1 + D2 + D3/t1 + t2 + t3

• → Average speed = 26 + 16 + 18/ 3 + 3 + 3

• → Average speed = 60/9

• → Average speed = 6.66m/s

Hence,

• Average speed of an object i.e 6.66m/s

Answer 2

Explanation:

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