Question

An object moves 26meter in first 3 second and 16meter in next 3second while it travels 18 meter in the last 3 second. Calculate the average speed????​

Answer 1

Given :-

• An object moves 26meter in first 3 second and 16meter in next 3second while it travels 18 meter in the last 3 second.

To find :-

• Average speed

Solution :-

★ In first case ★

• Distance travelled (D1) = 26m
• Time taken (t1) = 3s

★ In second case ★

• Distance travelled (D2) = 16m
• Time taken (t2) = 3s

★ In third case ★

• Distance travelled (D3) = 18m
• Time taken (t3) = 3s

As we know that

→ Average speed = Total distance

travelled/total time taken

→ Average speed = D1 + D2 + D3/t1 + t2 + t3

→ Average speed = 26 + 16 + 18/3 + 3 + 3

→ Average speed = 60/9

→ Average speed = 6.6 m/s

Hence,

• Average speed of abject is 6.6 m/s

Answer 2

Answer:

Given:-

• Average speed of an object

Solution:-

★In first case ★

• Distance travelled (D1) =26cm
• Time travelled (t+1) = 35

★In second case★

• Distance travelled (D2) = 16m
• Time taken (t+2) = 35

★In third case★

• Distance travelled (D3) =18cm
• Time taken (+2)= 35

As we know that :-

Average speed= total distance travelled / total time taken

Average speed = D1+D2+D3/ t1+ t2+t3

Average speed =26+16+18/3+3+3

Average speed =60/9

Average speed=6.6m/s

Hence,

$average \: speed \: of \: obect \: is \: 6.6ms$

hope it help uh dear✌࿐