An object moves along a straight line with an acceleration of 2m per s*s . if its initial speed is 10m per .what will be speed 5s later
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3
Given that:
Acceleration (a) = 2m/s^2
Initial velocity(i) = 10m/s
Time (t)= 5s
Let distance be s
Using second equation of motion
s=ut +(1/2)at^2
= (10)(5) + (1/2)(2)(5)^2
= 50 +25
=75
So, the distance covered by the body in 5s will be 75m.
Acceleration (a) = 2m/s^2
Initial velocity(i) = 10m/s
Time (t)= 5s
Let distance be s
Using second equation of motion
s=ut +(1/2)at^2
= (10)(5) + (1/2)(2)(5)^2
= 50 +25
=75
So, the distance covered by the body in 5s will be 75m.
Answered by
0
a=2m/s
u=10 m/s,t=5 sec
v=u+at
v= 10+2×5
v=20m/sec
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