Question

An object moves along a straight line with an acceleration of 2m/s2 . If its initial speed is 10m/s, what will be its speed 2s later?​

Answer 1

Given:-

Initial speed of an object (u)= 10m/s

Acceleration (a)= 2m/s^2

Time (t) =2 sec

To find :-

Final velocity of object (v)=?

$\underline{\bigstar{\sf{ By\ first\ equation\ of \ Motion}}}$

$\boxed{\textsf{\textbf{\dag\ \ v=u+at}}}$

Put the values in the given formula

$:\implies\sf v=u+at\\ \\ :\implies\sf v= 10+2\times 2\\ \\ :\implies\sf v= 10+4\\ \\ :\implies\sf v= 14m/s$

$\boxed{\textsf{\textbf{\dag\ \ Speed \ of \ object \ after \ 2s = 14m/s}}}$

Formula related to this !!

$\bullet\sf s= ut+\dfrac{1}{2}at^2\\ \\ \bullet\sf v^2=u^2+2as$

Where ,

•s = Distance

•u= Initial velocity

•v= final velocity

•a = acceleration

•t= time taken

Answer 2

$\bigstar$ Answer:

$\star$ Given:

⇒ Acceleration (a) = 2 m/s²

⇒ Initial velocity (u) = 10 m/s

⇒ Time (t) = 2 seconds

$\star$ To Find:

⇒ Final velocity (v)

$\star$ Solution:

We know that,

⇒ EQUATION OF MOTION

$\red{\boxed{\boxed{\rm v = u+at}}}$

According to the Question,

We are asked to find the speed of the object after 2 seconds

Using the above Formula,

$\implies \rm v = u + at$

Given that,

a = 2 m/s²

u = 10 m/s

t = 2 sec

Substituting the given values in the formula,

We get,

$\pink{\rm \implies v = 10+(2)(2)\;m/s}$

$\purple{\rm \implies v = 10+4\;m/s}$

$\blue{\rm \implies v = 14\;m/s}$

$\green{\boxed{\boxed{\rm v=14\;m/s}}}$

The velocity after 2 seconds in 14 m/s

Hence,

The Final Velocity (v) is

14 m/s