Question

An object moves along a straight line with an acceleration of 2 m/s^2. If its initial speed is 10 m/s, what distance will it cover in 2 seconds ?

Answer 1

Explanation:

Given :-

• acceleration,a = 2m/s²
• speed,v = 10m/s
• time, t = 2seconds

We know that,

$\boxed{speed = \frac{distance}{time}} \dashleftarrow(1)$

$dstance \: = speed \times time$

$\implies 10 \times 2$

$\implies \: \boxed{distance \: = 20m}$

Hence he will cover 20m in 2 seconds of time with its 10m/s initial speed

Answer 2

QUESTIONS-:

An object moves along a straight line with an acceleration of 2 m/s². If its initial speed is 10 m/s, what distance will it cover in 2 seconds ?

EXPLANATION-:

• Accelerations(a)=2 m/s²
• Initial velocity(v)=10 m/s
• Time (t)=2 s
• Distance covered(S)=?

Let's apply second equation of motion-:

S=ut+(0.5)at²

Putting values in the formula we get-:

S=10×2+(0.5)2×(2)²

S=20+4

S=24 m

So the distance covered is 24 metres

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