Question

An object moves along x-axis such that its position varying with time t is given as x=4t-t^2.The distance travelled by the object from t=0 to t=3s is

Answer 1

Distance travel by the object from zero second to 3 second is calculated by putting the value of time two times means when put the value 0 in equation then get X1 equal to 0 then put the value 3 second in equation then getX2= 3 metre
Then X2 - X1 equal 3 metre

Answer 2

Answer:

Explanation:

Velocity is d/dt(4t-t^2)=4-t, at t=o,v=4=initial velocity.

now acceleration at t=3,=d/dt(4-2into3) =0.

Now s = ut +1/2 at^2

=4into3 -0

=12.