An object moves around a circular path of radius 14m . Find i)the distance covered by the object.ii) the displacement of the object at the end of its motion.
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Answer:
88m is the distance covered.
Explanation:
Total Distance covered by the object = 2×pie×r
= 2×22/7×14
= 88m
Displacement = 0m
Because here final and initial position are same.
And we know that displacement is the shortest distance covered between the initial and final position.
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