Question

An object moves at a constant speed along a circular path in a horizontal XY plane,
with the centre at the origin. When the object is at x = -2m, its velocity is - (4m/s)j.
What is the object's acceleration when it is y = 2m
(a) – (8m/s)
(6) -(8m/s2) i
(C)-(4m/s)
(d) (4 m/s)​

Answer 1

Answer:

The position (displacement from origin) of an object (x) with respect to time (t) is given by the equation,

x = 2t2 + 5t

Determine:

a) The acceleration of the object

b) The displacement of the object at t = 5

c) The velocity of the object at t = 5