Question

An object moves at a constant speed along a circular path in a horizontal XY plane With the center at the origin if the velocity of the object when it reaches point p is (4m/s) j what is the direction of its acceleration at point p and q​

Answer 1

$\huge \underline \green{\sf{ Answer :- }}$

Velocity , v=−(4m/s)j^

at y=2 , centripetal acceleration magnitude,

a=rv2=2(4)2=216=8m/s2

So ar=−(8m/s2)j^

Answer 2

Answer:

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