Question

An object moves at a constant speed along a circular path in a horizontal xy plane, with the centre at the origin. When the object is at x=2m, its velocity is (4 m/s)j^. What is the object's acceleration when it is at y=2m.

Answer 1

Answer:

The centripetal acceleration is $a= -8\kap{i}\ m/s^2$

Explanation:

Given that,

Velocity $v = -(4 m/s)\kap{j}$

radius r = 2 m

The centripetal acceleration at y axis

$y = 2 m$

The acceleration is defined as:

$a = \dfrac{v^2}{r}$

$a = \dfrac{16}{2}$

$a= -8\kap{i}\ m/s^2$

Hence, The centripetal acceleration is $a= -8\kap{i}\ m/s^2$