an object moves from A to D along a rectangular path as shown ....the distance covered by the object and the displacement of the object
Answers
Answered by
1
Explanation:
Distance = Length of path travelled
=AB+BC
=15+9
=24km
Displacement = Shortest path from initial to final position
=AC
=
(AB)
2
+(BC)
2
{Pythagoras Theorem}
=
225+81
=17.5km
Answered by
2
Answer:
if we take assume a rectangular path of ABCD and let distance between A to B be 2km and B to C 1km as it is rectangular path than A to D distance will be 1km and D to C 2km if the objects follows the path ABC and then reaches D the total distance would be 5km because ; distance = total distance covered,
and if it reached D point just from A then displacement will be 1km as..displacement = distance between final point - initial point.
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