Question

an object moves from p to q in 10 sec with uniformal acceleration. velocity at p is 5m/s and velocity at q is 12m/s.... what is the acceleration? ??​

Answer 1

Aɴsᴡᴇʀ :

• Acceleration (a) = $\textsf{\textbf{\red{0.7\:m/s²}}}$

Gɪᴠᴇɴ :

• An object travelling from P to Q.

• Initial velocity (u) = 5 m/s

• Final velocity (v) = 12 m/s

• Time taken (t) = 10 sec

Tᴏ Fɪɴᴅ :

• Acceleration of the object (a)

Fᴏʀᴍᴜʟᴀ Usᴇᴅ :

• $\boxed{\bf{\purple{a = \dfrac{v-u}{t}}}}$

Sᴏʟᴜᴛɪᴏɴ :

➪ $\sf{\:a = \dfrac{v-u}{t}}$

➪ $\sf{\:a = \dfrac{12-5}{10}}$

➪ $\sf{\:a = \dfrac{7}{10} = \red{0.7\:m/s^2}}$

Answer 2

${{\underline{\underline{{\textsf{\textbf{Answer : }}}}}}}$

➡ The acceleration is 0.7m/s²

${{\underline{\underline{{\textsf{\textbf{Explanation : }}}}}}}$

Given that,

• An object moving in from point p to q in 10sec.
• velocity at point p is 5m/s and at point q is 12m/s.

❐ Acceleration of the object is given by :

$\bigstar{ \underline{ \boxed{ \sf \: a = \frac{v - u}{t} }}} \bigstar$

Where,

a (acceleration)

v (final velocity) = 12m/s

u (initial velocity) = 5m/s

t (time) = 10sec

❐ From the given values :

$\sf \longrightarrow \: a = \frac{12m/s - 5m/s}{10s}$

$\sf \longrightarrow \: a = \frac{7m/s}{10s}$

$\sf \longrightarrow \: a = 0.7m/s^2$

${\underline{\sf{Hence, \: the \: acceleration \: is \: {0.7m/s}^{2} }}}$