Physics, asked by khushimaurya774, 5 hours ago

An object moves from point A to C along the rectangle . Find the magnitude of the displacement of the object
{ A-B=12 cm
B-C=5 cm
C-D=12 cm
D-A=5 cm
it is a rectangle AB and CD length are same (12cm) & BC and DA breadth are same (5cm) ​

Answers

Answered by Yuseong
19

Answer:

13 cm

Explanation:

As per the provided information in the given question, we have :

  • An object moves from point A to C along the rectangle.
  • Length [ AB & CD ] is 12 cm and breadth [ BC & DA ] is 5 cm.

We are asked to calculate his displacement.

Displacement is the shortest distance from initial to the final position of the body. The shortest distance between two points is always a straight line. Here, object's initial position is A and final position is C. Thus, as the shortest distance between two points is always a straight line, so the diagonal of the rectangle (AC) will be the displacement.

Now, as angles of a rectangle measure 90° each. So, by using the Pythagoras property,

\longmapsto \rm { \ell^2 + b^2 = (Diagonal)^2} \\

\longmapsto \rm { (AB)^2 + (BC)^2 = (AC)^2} \\

\longmapsto \rm { (12 \; cm)^2 + (5 \; cm)^2 = (AC)^2} \\

\longmapsto \rm { 144 \; cm^2 + 25 \; cm^2 = AC^2} \\

\longmapsto \rm { 169 \; cm^2 = AC^2} \\

\longmapsto \rm { \sqrt{169 \; cm^2} = AC} \\

\longmapsto \bf { 13 \; cm= AC} \\

Magnitude of the displacement is 13 cm.

\rule{200}2

More Information :

  • Displacement is the shortest distance from initial to the final position of the body.
  • The shortest distance between two positions is always a straight line.
  • It is a vector quantity.
  • Its SI unit is m.
  • It is denoted by v.
  • Displacement = Velocity × Time
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