An object moves from point A to point C along the rectangle shown in the figure below. a) Find the distance covered by the moving object. b) Find the magnitude of the displacement of the object.
Answers
Explanation:
a) Distance = 8km ( 1 block = 1km)
a) Distance = 8km ( 1 block = 1km)∴ , Distance covered = 8km
a) Distance = 8km ( 1 block = 1km)∴ , Distance covered = 8kmb)Displacement -
a) Distance = 8km ( 1 block = 1km)∴ , Distance covered = 8kmb)Displacement -Let the displacement be d
a) Distance = 8km ( 1 block = 1km)∴ , Distance covered = 8kmb)Displacement -Let the displacement be d⇒ d² = 5² + 3² (Pythagoras Theorem )
a) Distance = 8km ( 1 block = 1km)∴ , Distance covered = 8kmb)Displacement -Let the displacement be d⇒ d² = 5² + 3² (Pythagoras Theorem )⇒ d² = 25 + 9
a) Distance = 8km ( 1 block = 1km)∴ , Distance covered = 8kmb)Displacement -Let the displacement be d⇒ d² = 5² + 3² (Pythagoras Theorem )⇒ d² = 25 + 9⇒ d² = 34
a) Distance = 8km ( 1 block = 1km)∴ , Distance covered = 8kmb)Displacement -Let the displacement be d⇒ d² = 5² + 3² (Pythagoras Theorem )⇒ d² = 25 + 9⇒ d² = 34Explanation:
a) Distance = 8km ( 1 block = 1km)∴ , Distance covered = 8kmb)Displacement -Let the displacement be d⇒ d² = 5² + 3² (Pythagoras Theorem )⇒ d² = 25 + 9⇒ d² = 34Explanation:Distance is the total distance covered hence it is 8km ie. 5km (a to b)+3km (b to c)
a) Distance = 8km ( 1 block = 1km)∴ , Distance covered = 8kmb)Displacement -Let the displacement be d⇒ d² = 5² + 3² (Pythagoras Theorem )⇒ d² = 25 + 9⇒ d² = 34Explanation:Distance is the total distance covered hence it is 8km ie. 5km (a to b)+3km (b to c)The magnitude of displacement will ONLY THE NUMBER , NOT THE UNIT .
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Answer:
where is figure guy....