Physics, asked by chandru2006, 9 months ago

An object moves from point A to point C along the rectangle shown in the figure below. a) Find the distance covered by the moving object. b) Find the magnitude of the displacement of the object.

Answers

Answered by mastermimd2
0

Explanation:

a) Distance = 8km        ( 1 block = 1km)

a) Distance = 8km        ( 1 block = 1km)∴ , Distance covered = 8km

a) Distance = 8km        ( 1 block = 1km)∴ , Distance covered = 8kmb)Displacement -

a) Distance = 8km        ( 1 block = 1km)∴ , Distance covered = 8kmb)Displacement -Let the displacement be d

a) Distance = 8km        ( 1 block = 1km)∴ , Distance covered = 8kmb)Displacement -Let the displacement be d⇒ d² = 5² + 3²              (Pythagoras Theorem )

a) Distance = 8km        ( 1 block = 1km)∴ , Distance covered = 8kmb)Displacement -Let the displacement be d⇒ d² = 5² + 3²              (Pythagoras Theorem )⇒ d² = 25 + 9

a) Distance = 8km        ( 1 block = 1km)∴ , Distance covered = 8kmb)Displacement -Let the displacement be d⇒ d² = 5² + 3²              (Pythagoras Theorem )⇒ d² = 25 + 9⇒ d² = 34

a) Distance = 8km        ( 1 block = 1km)∴ , Distance covered = 8kmb)Displacement -Let the displacement be d⇒ d² = 5² + 3²              (Pythagoras Theorem )⇒ d² = 25 + 9⇒ d² = 34Explanation:

a) Distance = 8km        ( 1 block = 1km)∴ , Distance covered = 8kmb)Displacement -Let the displacement be d⇒ d² = 5² + 3²              (Pythagoras Theorem )⇒ d² = 25 + 9⇒ d² = 34Explanation:Distance is the total distance covered hence it is 8km ie. 5km (a to b)+3km (b to c)

a) Distance = 8km        ( 1 block = 1km)∴ , Distance covered = 8kmb)Displacement -Let the displacement be d⇒ d² = 5² + 3²              (Pythagoras Theorem )⇒ d² = 25 + 9⇒ d² = 34Explanation:Distance is the total distance covered hence it is 8km ie. 5km (a to b)+3km (b to c)The magnitude of displacement will ONLY THE NUMBER , NOT THE UNIT .

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Answered by devansh96kkr
0

Answer:

where is figure guy....

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