Question

An object moves from y = 12 m to y = 15 m in 5 s. What can be said about the magnitude of displacement and the path length?​

Answer 1

Answer:

Positions of the particle are

r1=6iˆ+8jˆ and r2=12iˆ+10jˆ

∴Δr=r2−r1=6iˆ+2jˆ⇒|Δr|=40−−√

θ=tan−1(ΔyΔx)=tan−1(13)=18.43∘

Answer 2

Answer:

the magnitude of displacement and the path length will be 3m

Explanation:

The magnitude of displacement can be calculated by finding the difference between the final position and the initial position, which is:

Magnitude of displacement = (final position - initial position)

= (15 m - 12 m) = 3 m

Therefore, the magnitude of displacement is 3 meters.

• If the object moves in a straight line from point A to point B, then the path length will be equal to the magnitude of displacement, which is 3 meters in this case.

This is because the object moves directly from y = 12 m to y = 15 m, which means it does not change direction during its motion. Therefore, the path it takes is a straight line, and its length is equal to the distance between the starting point and the ending point.

Since the magnitude of displacement is also 3 meters, we can conclude that the path length is equal to the magnitude of displacement.

Note: However, this is only true if the object moves in a straight line. If the object follows a curved path, the path length will be greater than the magnitude of displacement.

To learn more about displacement from the link below

https://brainly.in/question/1210804

To learn more about motion from the link below

https://brainly.in/question/10642866

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