Question

An object moves on a circular path such that the distance covered is given by S = (0.5t2 + 2t) m, here t is time in s. If radius of circle is 4 m, then initial acceleration of object is

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Answer 1

Answer:

1 m/s^2

Step-by-step explanation:

distance by time is velocity. therefore

ds/dt = dv

ds/dt = t+2.

velocity by time = acceleration

dv/dt = 1

so, answer is 1m/s^2

Answer 2

Step-by-step explanation:

$.21y) {25}^{2} 2576121. \\ . = 3450(6460444y(10.)(25)(y - 4) \\ 2 - 85 < 2.55.$