Question

An object moves quarter of a circle of radius 7 m. Find its distance and displacement.

Answer 1

distance =
$\frac{90}{360} \times 2\pi \times 7m \\ = \frac{1}{4} \times 2 \times \frac{22}{7} \times 7m \\ = 11m$
displacement =
$\sqrt{ {7}^{2} + {7}^{2} } \: m = \sqrt{2. {7}^{2} } \: m = 7 \sqrt{2} m$