Question

an object moves with a uniforn speed v1 for the time t and then moves with a uniform speed v2 for further time t .find the average speed

Answer 1

distance=speed/time
so, v1/t=d1
and v2/t=d2.
average speed=total distance/ total time
so,d1+d2/t+t

Answer 2

The average speed pf the car for the whole journey is $\frac{(v1+v2)}{2} m/s$

Given,

Speed for the first part of the journey=v1

Time for the first part of the journey=t

Speed for the second part of the journey=v2

Time for the second part of the journey=t.

To find,

the average speed during the whole journey.

Solution:

• Average speed of an object is defined as the ratio of total distance covered to the total time taken to cover the total distance.
• Average speed is a scalar quantity.

• Average velocity of an object is defined as the ratio of total displacement covered to the total time taken to cover the total distance.
• Average velocity is a vector quantity.

Average speed=Total distance covered/Total time taken

The distances covered will be:

Speed=Distance/Time

$v1=\frac{d1}{t} \\d1=v1Xt\\d1=v1t$

$v2=\frac{d2}{t} \\d2=v2Xt\\d2=v2t$

Average speed=$\frac{(v1t+v2t)}{t+t)}$

$=\frac{t(v1+v2)}{2t} \\=\frac{(v1+v2)}{2}$.

Hence, the average speed=$\frac{(v1+v2)}{2} m/s$.

#SPJ2