An object moves with an accelation of 2mpersec if its initiqk speed is 10mpersec rind its sp3ed 5 sec lste4
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a=2 m/s
t=5 sec
u=10m/s
that u put the equation
t=5 sec
u=10m/s
that u put the equation
Answered by
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1st case:-
10 m/s for 5 seconds
s = vt
= 10×5
= 50m
2nd case:-
5 m/s for 10 seconds
s = vt
= 5×10
= 50 m
Average velocity = total distance/total time
= 50+50/5+10
= 100/15
= 6.66 m/s
Hope it helps you ☺
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10 m/s for 5 seconds
s = vt
= 10×5
= 50m
2nd case:-
5 m/s for 10 seconds
s = vt
= 5×10
= 50 m
Average velocity = total distance/total time
= 50+50/5+10
= 100/15
= 6.66 m/s
Hope it helps you ☺
Please mark as Brainliest ☺
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