Question

An object moves with an initial of 20 m/s accelerates uniformly at 5 m/s2 in the direction of it's motion for a distance of 10 m. what is the final velocity of the object?

Answer 1

Answer:

Initial velocity (u)= 25m/s

Final velocity (v)= 45m/s

Time taken(t)= 12s

Distance covered (s)= ?

Solution

Acceleration a =( v — u )/t

a= (45 —25)/12

a= 20/12 m/s^2

s = ut + 1/2at^2

Now use second equation of motion

s= u×t + 1/2 × a × t^2

s = 12× 25 + 1/2 × 20/12 × 12^2

s = 300 + 10 × 12

s = 300 + 120

s = 420m

Ans) The distance covered by the body is 420m.

Answer 2

The final velocity of the object is 22.36m/s

Given:- initial speed (u) = 20m/s

             acceleration (a)= 5m/$s^{2}$

             distance (s) = 10m

To Find:-  Final velocity of the object (v)

Formula Used:- Using third equation of motion

                          $v^{2}$ - $u^{2}$ = 2*a*s

Solution:-

u = 20m/s

a = 5m/$s^{2}$

s = 10m

$v^{2}$ - $20^{2}$ = 2 * 5 * 10

$v^{2}$ - 400 = 100

$v^{2}$ = 100+400

$v^{2}$ = 500

v = $\sqrt{500}$

v = 22.36 m/s

The final velocity of the object is 22.36m/s