Question

An object moving 6m/s excute an acceleration 2m/s square in next 3 sec . How much distance it covered? Find its velocity after 3sec

Answer 1

Answer:

As initial velocity U = 6m/s

As acceleration A = 2m/s²

As time T = 3

Let's find the distance S = UT + \huge\frac{1}{2} A(T)²

S = 6 × 3 + \huge\frac{1}{2} × 2 × 3²

S = 18 + 9

distance S = 27m

Answer 2

Explanation:

u = 6m/s

v = ?

t = 3sec

a = 2m/s^2

s = ?

now,

v = u+at

v = 6+2(3)

V = 12m/s

and,

S = ut+1/2at^2

S = 6(3) + 2×3^2

S= 18+2× 9

S = 18+18

S = 36m