Question

An object moving at 13m/s slows uniformly at the rate of 2m/s each second for a time of 6 sec. The average speed during the 6 sec is

Answer 1

your answer is here ....

velocity of object at 5s = 13 + (-2)5=13-10=3 m/s

final velocity(v) = 3 m/s

velocity of object at 6 s = 3 + (-2) = 1

initial veloctity(u) = 1 m/s

average velocity = u + v / 2
= 1 + 3 /2
= 4/2
=2

so average velocity of object at 6 seconds = 2 m/s

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Answer 2

Answer:

7 m/s

Explanation:

Given:

Initial Velocity u=13 m/s

Acceleration a= -2 m/s^2

Time taken t= 6 s

Distance Travelled s=ut+at^2/2

                                 = 13(6) - 1/2 * 2*(6)^2

                                 = 78 - 36

                                 = 42 m

We know that,

Avg. speed = Distance travelled / Time taken

                   = 42/6

Avg.speed = 7 m/s