Question

An object moving at a velocity 24 ms⁻¹ is brought to a halt in 8 seconds by applying a force in opposite direction to the motion. Calculate the acceleration.

Answer 1

hola user here is ur answer

, velocity (u): 24ms^-1
time(t) = 8s

then we know that

v= u +at

a = v-u÷t

a=0 - 24÷ 8= -24÷8 = -3ms^-2

a = -13ms^-2

hope it helps u

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