An object moving horizontally with kinetic energy of 800J experience constant opposing force of 100N while moving from one point x to another point y. xy is 2m what is the energy of the object at y?
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Answer:
In passing 2m path against force 100N the.
Particle will do work and lose KE by the amount 100×2=200 J
So,
Energy of the particle at b will be 800-200=600J
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