an object moving in a circular path of radius 10 m and cover exactly half of the circular path then what will be its distance and displacement
Answers
Answered by
0
Answer:
3.20m/s
Explanation:
Net acceleration is the resultant acceleration of centripetal acceleration and tangential acceleration thus find both of them as follows:
A
− be centripetal acceleration.
A
t
− be tangential acceleration
A
net
=
(A
c
2
+A
t
2
)
Now then,
A
c
is
R
V
2
=
10
25
=2.5m/s
2
A
t
is given as 2.m/s
2
, thus
A
net
=
(2.5
2
+2
2
)
=3.20m/s
2
.
Answered by
1
Answer:
31.4m and 20m
Explanation:
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