Question

An object moving in a circular path of radius 5m if it completes two full cycle calculate the distance and displacement of the object

Answer 1

GIVEN :

• Radius of the circular path = 5 m

TO FIND :

• Distance travelled after two full revolutions by the object

• Displacement of the object.

Concept :

Distance is the actual path covered by the object and is a scalar quantity so it doesn't have direction. Distance can't be zero in any case.

Displacement is the shortest path covered by the object. It is a vector quantity. It can be zero.

SOLUTION :

In a circular path the distance is equal to the circumference of the circle. Hence,

$Distance = 2\pi r \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \times 3.14 \times 5 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 31.4 \: m$

For 1 revolution of the circle, distance = 31.4 m

For 2 revolution the distance = 2×31.4 = 62.8m

And,

As the object moves from the same point and reaches to the same point so its displacement is zero.